13x+736+2x^2+64x=12A

Solution for 13x+736+2x^2+64x=12A equation:

13x+736+2x^2+64x=12

We move all terms to the left:

13x+736+2x^2+64x-(12)=0

We add all the numbers together, and all the variables

2x^2+77x+724=0

a = 2; b = 77; c = +724;
Δ = b2-4ac
Δ = 772-4·2·724
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(77)-\sqrt{137}}{2*2}=\frac{-77-\sqrt{137}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(77)+\sqrt{137}}{2*2}=\frac{-77+\sqrt{137}}{4}
$